After all, people have been solving that equation ... rewrite the zero as (x-S)(x-R) and the rest follows very logically. The only real problem is not many quadratic equations have A=1.

\(y = x + 3\) is a linear equation and \(y = x^2 + 3x\) is a quadratic equation. If the product of two numbers is zero, then one or both numbers must also be equal to zero. To solve, put each ...

To find solutions from graphs, look for the point where the two graphs cross one another. This is the solution point. For example, the solution for the graphs \(y = x + 1\) and \(x + y = 3\) is ...