2016年6月21日 · A reaction in which the same species is both oxidised and reduced. A great example is chlorine mixing with water. Cl_2 + H_2O -> HCl + HClO Elemental chlorine (Cl_2) has a redox number of 0. In HCl, it has a redox number of -1 And in HClO it has a redox number of +1 Therefore chlorine has been both oxidised and reduced in the same reaction. This is …

2014年2月28日 · You can use the oxidation number method to balance an equation for a disproportionation reaction. > In a disproportionation reaction, the same substance forms two different redox products. For example, chlorine gas reacts with dilute sodium hydroxide to form sodium chloride, sodium chlorate, and water: "Cl"_2 + "NaOH" → "NaCl" + "NaClO"_3 + …

2016年6月21日 · You balance them stoichiometrically, and in fact you follow the same procedure of separate redox processes for oxidation and reduction. Chlorine gas is known to disproportionate to chlorate and chloride ion: Reduction (i): 1/2Cl_2 + e^(-) rarr Cl^(-) Oxidation (ii): 1/2Cl_2(g) + 3H_2O(l) rarr ClO_3^(-) + 6H^(+) +5e^(-) So mass and charge are balanced …

2017年2月18日 · 4H_3PO_3 ----------> 3H_3PO_4 + PH_3 Disproportionation is a type of redox reaction where an element from a reaction undergoes both oxidation and reduction to form two different types of products. Similarly in case of H_3PO_3 gives two products on diproportionation on heating. On heating H_3PO_3 it undergoes disproportionation reaction to give ortho …

2018年6月25日 · I think you refer to the disproportionation of elemental chlorine to chloride anion, and hypochlorous acid.... And we can go thru the rigmarole of redox transtions… "Elemental chlorine is reduced (i):" 1/2Cl_2 +e^(-) rarr Cl^- "Elemental chlorine is oxidized to hypochlorous acid (ii):" 1/2Cl_2 + H_2O(l) rarr HOstackrel(+I)Cl+ +H^+ +e^(-) And we adds (i)+(ii) to get....

2016年8月10日 · I usually write 2 separate redox reaction: one an oxidation; the other a reduction. For example, let's take the action of hydroxide on chlorine gas. Chloride ion is produced, a reduction: 1/2Cl_2 + e^(-) rarr Cl^- (i) But also chlorate ion is produced, an oxidation from Cl_2^(0) to Cl^(V+) 1/2Cl_2 + 3H_2O rarr ClO_3^− + 6H^+ + 5e^- We add 6xxHO^- to get: 1/2Cl_2 + …

2018年1月27日 · You're actually dealing with a disproportionation reaction here. In a disproportionation reaction, the same element undergoes both oxidation and reduction. In this case, manganese(VI) is reduced to manganese(IV) and oxidized to manganese(VII).

2017年11月11日 · How does nitrous acid disproportionate? Chemistry. 1 Answer anor277 Nov 11, 2017 ...

2017年4月7日 · When listed -ve to +ve like this a general rule to predict the outcome of a redox reaction is to say "bottom left will oxidise top right." On this basis we can say that #sf(MnO_4^-)# will not be able to oxidise #sf(MnO_2)# to #sf(MnO_4^(2-)# because the #sf(E^@)# value is not +ve enough. However, these values refer to standard conditions ...

2018年6月12日 · The equivalent weight of #"H"_2"O"_2# in this reaction is 34.01 g. Answer link. Related questions.