2020年10月7日 · Re: Solute versus solvent Post by Mackenzie Stockton 2H » Thu Oct 08, 2020 4:55 am Hi, like others have said, the solute is the substance that is dissolved in the solvent.

2020年10月26日 · Solute vs Solvent. Moderators: Chem_Mod, Chem_Admin. 7 posts • Page 1 of 1. Aaron Akhavan-Dis1B Posts: 106

2022年1月4日 · Yes, aqueous solutions are included in equilibrium constant equations, Kc, because an aqueous solution can have varying concentrations of solute in a solvent. For instance, salt as a solute can be added to the water solvent to get a higher concentration, which would change the factors that contribute to the ratio of reactants to products.

2019年9月28日 · When dilution occurs, you are only adding water (or solvent) to the solution. Whatever the solute is remains unchanged in amount. Only solvent has been added. Therefore, the moles of solute remains the same prior to and after dilution. This means that M1V1 = M2V2, and by knowing 3 of those values, you can find the last one easily.

2018年10月5日 · Molarity is moles of solute per liter of solution(mol/L). Molality is the moles of solute per kilogram of solvent (mol/kg). While both have the same values in the numerator, they differ in the denominator. For the denominator of molarity, you are looking at the combined volume of the solvent and solute, or the total solution.

2021年1月16日 · The reasoning behind why the solvent is important is because there is such an incredibly high concentration of solvent, when a solute interacts, the interaction is not large enough to make any major reduction in solvent concentration. While the solvent concentration may change slightly, it is not impactful enough to be included in K calculations.

2024年2月19日 · Kinetics vs. Thermodynamics Controlling a Reaction General Rate Laws Method of Initial Rates (To Determine n and k) Zero Order Reactions First Order Reactions Second Order Reactions Reaction Mechanisms, Reaction Profiles Arrhenius Equation, Activation Energies, Catalysts *Enzyme Kinetics

2020年10月9日 · So knowing that molarity = (moles of solute)/(liters of solution) and rearranging to solve for moles of solute gets us moles of solute = (molarity)(liters of solution) or MV. Then we get the equation M1V1 = M2V2 where M1/M2 are initial/final molarities and V1/V2 are initial/final volumes of solution as the moles of solute remain the same before ...

2020年10月11日 · So, basically, M (molarity) = n (moles of solute) / V (volume of solution). In the question that deals with dilution of solution, n (moles of solute) does not change even if we add more solution to the existing solution to dilute it. From this, we can derive the formula M(initial)*V(initial) = M(final)*V(final).

2020年10月12日 · Moles will stay the same as long as you do not add more solute. However, say you're adding more water, which will increase the volume, that would decrease the molarity because adding more solvent decreases the concentration. So despite there being the same number of moles, the molarity is less.