As O 2 − ions forms ccp, spinel has 4 negative ions in its structure. So, total positive charge should be 8. It has one M g + 2 ion occupying one-eight of the tetrahedral holes and 2 A l + 3 ions occupying one-half of the octahedral holes. So, the compound is M g A l 2 O 4.

The incorrect statement about inverse spinel structure is (1) Fe, O, is an example of inverse spinel structure (2) 25% tetrahedral voids are occupied by ions (3) 50% octahedral voids are occupied by ions (4) Fe3+ ions are equally distributed in between …

In spinel structure, O 2-ions are cubic closed packed, whereas 1/8 th of the tetrahedral holes are occupied by A 2 + cations and 1/2 of the octahedral holes are occupied by cations B 3 +. The general formula of this compound is

For the spinel structure (M g A l 2 O 4), the correct statement is/are : 50 % of the octahedral voids are occupied by ions; A l 3 + ions are equally distributed in tetrahedral voids and octahedral voids; Oxide ions occupy ccp lattice; 12.5 % of the tetrahedral voids are occupied by ions

Click here👆to get an answer to your question ️ In the spinel structure, oxides ions are cubical - closest packed whereas 1 / 8th of tetrahedral voids are occupied by A^2 + cation and 1 / 2 of octahedral voids are occupied by B^3 + cations. The general formula of the compound having spinel structure is :

In 2: 3 spinel structure General formula is A + 2 B + 3 2 O 4 A + 2 : 1 8 × T e t r a h e d r a l v o i d s B + 3 : 1 2 × O c t a h e d r a l v o i d s O 2 − : F C C l a t t i c e Only M g + 2 A l + 3 2 O 4 and C o 2 + ( C o 3 + ) 2 O 4 satisfies the above conditions.

In spinel structure, oxides ions form fcc lattice, whereas 1 8 th of tetrahedral holes are occupied by cations A 2 + and 1 2 of octahedral holes are occupied by cations B 3 + ions. The general formula of the compound having spinel structure is

A certain ionic compound is formed in the Spinel structure in nature in which O 2 − ionic constitute CCP lattice A 2 + ions occupy 1 / 8 t h of the tetrahedral voids and B 3 + ions occupy 1 / 2 of the octahedral voids . Find out total +ve charge contained in two-unit cell of given ionic structure.

In the normal spinel structure the oxide ions are arranged in ccp pattern. The Zn 2+ ions occupy on-eighth of the tetrahedral holes and one half of the octahedral voids are occupied by Al 3+. Give the formula of the spinel.

In spinel structure, O 2-ions are cubic closed packed, whereas 1/8 th of the tetrahedral holes are occupied by A 2 + cations and 1/2 of the octahedral holes are occupied by cations B 3 +. The general formula of this compound is